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Math Gang

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proof that the square root of any non-perfect square is irrational

This is a proof by contradiction.


First, let's prove the square root


Let P/Q=the square root of 2, where P and Q are positive integers and P/Q is fully simplified.


P^2/Q^2=2


P^2=2Q^2


This means P^2 is even, meaning P is even, as P^2=2* A number.


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True

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1.0000000000000000000000000000000001 ^ 1000000000000000000000000000000000 = e

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